Plot a graph between V and I and calculate the resistance of the resistor. Answer: (Graph Method) : Plot V on Y-axis and I on X-axis. The slope of the V-I graph gives the Resistance. Slope = $\frac\Delta V\Delta I$. Taking two points from the data (e.g., $V_1=1.6, I_1=0.5$ and $V_2=13.2, I_2=4.0$): $$R = \frac13.2 - 1.64.0 - 0.5 = \frac11.63.5 = 3.31 \ \Omega \text (approx)$$ The resistance of the resistor is approximately 3.3 $\Omega$ .
If measuring across the 12 $\Omega$ resistor (assuming a typo in the question text or specific context): Voltage across $12 \ \Omega$ = $I \times R = 0.2 \times 12 = 2.4 \text V$. The reading will be 2.4 V . electricity ncert solutions class 10
**Q17. An electric heater of resistance 8 $\Omega$ draws 15 A from the Plot a graph between V and I and
Answer: Given:
Answer: (i) Series Circuit (6 V): Total Resistance = $1 + 2 = 3 \ \Omega$. Current in circuit ($I$) = $\frac6 \text V3 \ \Omega = 2 \text A$. Power in $2 \ \Omega$ resistor ($P_1$) = $I^2 R = (2)^2 \times 2 = 4 \times 2 = 8 \text W$. Slope = $\frac\Delta V\Delta I$